5x^2-4x+20=0

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Solution for 5x^2-4x+20=0 equation:


Simplifying
5x2 + -4x + 20 = 0

Reorder the terms:
20 + -4x + 5x2 = 0

Solving
20 + -4x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
4 + -0.8x + x2 = 0

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + -0.8x + -4 + x2 = 0 + -4

Reorder the terms:
4 + -4 + -0.8x + x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -0.8x + x2 = 0 + -4
-0.8x + x2 = 0 + -4

Combine like terms: 0 + -4 = -4
-0.8x + x2 = -4

The x term is -0.8x.  Take half its coefficient (-0.4).
Square it (0.16) and add it to both sides.

Add '0.16' to each side of the equation.
-0.8x + 0.16 + x2 = -4 + 0.16

Reorder the terms:
0.16 + -0.8x + x2 = -4 + 0.16

Combine like terms: -4 + 0.16 = -3.84
0.16 + -0.8x + x2 = -3.84

Factor a perfect square on the left side:
(x + -0.4)(x + -0.4) = -3.84

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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